Question:
Factorise:
(3x − 4y)2 − 25z2
Solution:
We have:
$(3 x-4 y)^{2}-25 z^{2}=(3 x-4 y)^{2}-(5 z)^{2}$
$=\{(3 x-4 y)+5 z\}\{(3 x-4 y)-5 z\}$
$=(3 x-4 y+5 z)(3 x-4 y-5 z)$
$\therefore(3 x-4 y)^{2}-25 z^{2}=(3 x-4 y+5 z)(3 x-4 y-5 z)$
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