Factorise:

Question:

Factorise:
x3 − 64x

Solution:

We have:

$x^{3}-64 x=x\left(x^{2}-64\right)$

$=x\left\{(x)^{2}-(8)^{2}\right\}$

$=x(x+8)(x-8)$

$\therefore x^{3}-64 x=x(x+8)(x-8)$

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