Factorise:

Question:

Factorise:
p2 − 4p − 77

Solution:

The given expression is $p^{2}-4 p-77$.

Find two numbers that follow the conditions given below:

Sum $=-4$

Product $=-77$

Clearly, the numbers are $-11$ and 7 .

$p^{2}-4 p-77=p^{2}-11 p+7 p-77$

$=p(p-11)+7(p-11)$

$=(p-11)(p+7)$

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