Factorise:

Question:

Factorise:

$4 a^{2}-9 b^{2}-2 a-3 b$

 

Solution:

$4 a^{2}-9 b^{2}-2 a-3 b$

$=(2 a)^{2}-(3 b)^{2}-1(2 a+3 b)$

$=(2 a+3 b)(2 a-3 b)-1(2 a+3 b) \quad\left[a^{2}-b^{2}=(a+b)(a-b)\right]$

$=(2 a+3 b)[(2 a-3 b)-1]$

$=(2 a+3 b)(2 a-3 b-1)$

 

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