Factorise:

Question:

Factorise:
(2x + 5y)2 − 1

Solution:

We have:

$(2 x+5 y)^{2}-1=(2 x+5 y)^{2}-(1)^{2}$

$=\{(2 x+5 y)+1\}\{(2 x+5 y)-1\}$

$=(2 x+5 y+1)(2 x+5 y-1)$

$\therefore(2 x+5 y)^{2}-1=(2 x+5 y+1)(2 x+5 y-1)$

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