Question:
Factorise:
3z2 − 10z + 8
Solution:
The given expression is $3 z^{2}-10 z+8$.
Find two numbers that follow the conditions given below:
Sum $=-10$
Product $=3 \times 8=24$
Clearly, the numbers are $-6$ and $-4$.
$3 z^{2}-10 z+8=3 z^{2}-6 z-4 z+8$
$=3 z(z-2)-4(z-2)$
$=(3 z-4)(z-2)$
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