Question:
Factorise:
6p2 + 11p − 10
Solution:
The given expression is $6 p^{2}+11 p-10$.
Find two numbers that follow the conditions given below:
Sum $=11$
Product $=6 \times-10=-60$
Clearly, the numbers are 15 and $-4$
$6 p^{2}+11 p-10=6 p^{2}+15 p-4 p-10$
$=3 p(2 p+5)-2(2 p+5)$
$=(2 p+5)(3 p-2)$
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