Question:
Factorise:
$40+3 x-x^{2}$
Solution:
$-x^{2}+3 x+40$
$=-x^{2}+8 x-5 x+40$
$=-x(x-8)-5(x-8)$
$=(x-8)(-x-5)$
$=(8-x)(x+5)$
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