Factorise:
Question:

Factorise:
p2 − 10p + 25

Solution:

We have:

$p^{2}-10 p+25=p^{2}-2 \times p \times 5+(5)^{2}$

$=(p-5)^{2}$

$\therefore p^{2}-10 p+25=(p-5)^{2}$

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