Question:
Factorise:
3 + 23z − 8z2
Solution:
The given expression is $3+23 z-8 z^{2}$.
Find two numbers that follow the conditions given below:
Sum $=23$
Product $=3 \times-8=-24$
Clearly, the numbers are 24 and $-1$.
$3+23 z-8 z^{2}=3+24 z-z-8 z^{2}$
$=3(1+8 z)-z(1+8 z)$
$=(1+8 z)(3-z)$
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