Question:
Factorise:
63a2b2 − 7
Solution:
We have:
$63 a^{2} b^{2}-7=7\left(9 a^{2} b^{2}-1\right)$
$=7\left\{(3 a b)^{2}-(1)^{2}\right\}$
$=7(3 a b+1)(3 a b-1)$
$\therefore 63 a^{2} b^{2}-7=7(3 a b+1)(3 a b-1)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.