Factorize:
$9 a^{2}+3 a-8 b-64 b^{2}$
$9 a^{2}+3 a-8 b-64 b^{2}=9 a^{2}-64 b^{2}+3 a-8 b$
$=(3 a)^{2}-(8 b)^{2}+(3 a-8 b)$
$=(3 a-8 b)(3 a+8 b)+1(3 a-8 b)$
$=(3 a-8 b)(3 a+8 b+1)$
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