Question:
Factorize:
$3 a^{3} b-243 a b^{3}$
Solution:
$3 a^{3} b-243 a b^{3}=3 a b\left(a^{2}-81 b^{2}\right)$
$=3 a b\left[a^{2}-(9 b)^{2}\right]$
$=3 a b(a-9 b)(a+9 b)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.