Question:
Figure shows a ray of light as it travels from medium A to medium B. Refractive index of the medium B relative to medium A is
(a) $\sqrt{3} / \sqrt{2}$
(b) $\sqrt{2} / \sqrt{3}$
(c) $1 / \sqrt{2}$
(d) $\sqrt{2}$
Solution:
(a).
Explanation. $\mathrm{n}_{\mathrm{BA}}=\frac{\sin i}{\sin r}=\frac{\sin 60^{\circ}}{\sin 45^{\circ}}=\frac{\sqrt{3} / 2}{1 / \sqrt{2}}=\frac{\sqrt{3}}{\sqrt{2}}$
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