Find the area of Fig. 20.25, in square cm,

The given figure is:

Construction : Connect A to D.

Then, we have: Area of the given figure $=$ (Area of rectangle $\mathrm{ABCD}+$ Area of the semicircle) $-$ (Area of $\triangle \mathrm{AED}$ ).

$\therefore$ Total area of the figure $=($ Area of rectangle with sides $10 \mathrm{~cm}$ and $10 \mathrm{~cm})$

$+\left(\right.$ Area of semicircle with radius $\left.=\frac{10}{2}=5 \mathrm{~cm}\right)-($ Area of triangle AED with base $6 \mathrm{~cm}$ and height $8 \mathrm{~cm})$

$=(10 \times 10)+\left(\frac{1}{2} \times \frac{22}{7} \times 5^{2}\right)-\left(\frac{1}{2} \times 6 \times 8\right)$

$=100+39.3-24$

$=115.3 \mathrm{~cm}^{2}$