Find the area of the triangle whose base measures 24 cm and the corresponding height measures 14.5 cm.

Given: base $=24 \mathrm{~cm}$, correponding height $=14.5 \mathrm{~cm}$

Area of a triangle $=\frac{1}{2} \times$ base $\times$ coresponding height

$=\frac{1}{2} \times 24 \times 14.5$

$=174 \mathrm{~cm}^{2}$