Question.
Find the cost of digging a cuboidal pit $8 \mathrm{~m}$ long, $6 \mathrm{~m}$ broad and $3 \mathrm{~m}$ deep at the rate of Rs 30 per $\mathrm{m}^{3}$.
Solution:
The given cuboidal pit has its length $(l)$ as $8 \mathrm{~m}$, width $(b)$ as $6 \mathrm{~m}$, and depth $(h)$ as $3 \mathrm{~m}$.
Volume of pit $=1 \times b \times h$
$=(8 \times 6 \times 3) \mathrm{m}^{3}=144 \mathrm{~m}^{3}$
Cost of digging per $\mathrm{m}^{3}$ volume $=$ Rs 30
Cost of digging $144 \mathrm{~m}^{3}$ volume $=\mathrm{Rs}(144 \times 30)=\mathrm{Rs} 4320$
The given cuboidal pit has its length $(l)$ as $8 \mathrm{~m}$, width $(b)$ as $6 \mathrm{~m}$, and depth $(h)$ as $3 \mathrm{~m}$.
Volume of pit $=1 \times b \times h$
$=(8 \times 6 \times 3) \mathrm{m}^{3}=144 \mathrm{~m}^{3}$
Cost of digging per $\mathrm{m}^{3}$ volume $=$ Rs 30
Cost of digging $144 \mathrm{~m}^{3}$ volume $=\mathrm{Rs}(144 \times 30)=\mathrm{Rs} 4320$
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