Find the equation of the circle with centre (0, 2) and radius 2
Question:

Find the equation of the circle with centre (0, 2) and radius 2

Solution:

The equation of a circle with centre (hk) and radius is given as

$(x-h)^{2}+(y-k)^{2}=r^{2}$

It is given that centre (hk) = (0, 2) and radius (r) = 2.

Therefore, the equation of the circle is

$(x-0)^{2}+(y-2)^{2}=2^{2}$

$x^{2}+y^{2}+4-4 y=4$

$x^{2}+y^{2}-4 y=0$