Find the equation of the line for which

Given: p = 5 and ∝ = 1350

Here $p$ is the perpendicular that makes an angle $\propto$ with positive direction of $x$-axis, hence the equation of the straight line is given by:

Formula used

$x \cos \propto+y \sin \alpha=p$

$x \cos 1350+y \sin 1350=5$

i.e; $\cos 1350=\cos ((4 \times 360)-90)=\cos ((4 \times 2 \pi)-90)=\cos 90$

similarly, $\sin 1350=\sin ((4 \times 360)-90)=\sin ((4 \times 2 \pi)-90)=-\sin 90$

hence, $x \cos 90+y(-\sin 90)=5$

$x \times(0)-y \times 1=5$

Hence The required equation of the line is y=-5.