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Class 8-9-10, JEE & NEET
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Find the equation of the line which cuts off intercepts 4 and -6 on the x-axis and y-axis respectively.
To Find:The equation of the line with intercepts 4 and -6 on the x-axis and yaxis respectively.
Given : Let a and b be the intercepts on $x$-axis and $y$-axis respectively.
Then, $x$-intercept be $a=4$
$y$-intercept be $b=-6$
we know that intercept form of a line is given by
$-3 x+2 y=-12$
$3 x-2 y-12=0$
Hence 3x – 2y -12 = 0 is the required equation of the given line.