Find the median of the data:

Numbers are 41, 43, 127, 99, 71, 92, 71, 58, 57

Arranging the numbers in ascending order

41, 43, 57, 58, 71, 71, 92, 99, 127

n = 9 (odd)

$\therefore$ Median $=\left(\frac{\mathrm{n}+1}{2}\right)^{\text {th }}$ value

$=\left(\frac{9+1}{2}\right)^{\text {th }}$ value

$=5^{\text {th }}$ value $=71$