Find the sum to n terms of the series 1 × 2 + 2 × 3 + 3 × 4 + 4 × 5 + …
Question:

Find the sum to $n$ terms of the series $1 \times 2+2 \times 3+3 \times 4+4 \times 5+\ldots$

Solution:

The given series is $1 \times 2+2 \times 3+3 \times 4+4 \times 5+\ldots$

$n^{\text {th }}$ term, $a_{n}=n(n+1)$

$\therefore S_{n}=\sum_{k=1}^{n} a_{k}=\sum_{k=1}^{n} k(k+1)$

$=\sum_{k=1}^{n} k^{2}+\sum_{k=1}^{n} k$

$=\frac{n(n+1)(2 n+1)}{6}+\frac{n(n+1)}{2}$

$=\frac{n(n+1)}{2}\left(\frac{2 n+1}{3}+1\right)$

$=\frac{n(n+1)}{2}\left(\frac{2 n+4}{3}\right)$

$=\frac{n(n+1)(n+2)}{3}$

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