Question:
Find the value
$p^{3}+27$
Solution:
$=p^{3}+3^{3}$
$\therefore\left[a^{3}+b^{3}=(a+b)\left(a^{2}-a b+b^{2}\right)\right]$
$=(p+3)\left(p^{2}-3 p-9\right)$
$\therefore p^{3}+27=(p+3)\left(p^{2}-3 p-9\right)$
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