$\left(4 x^{2}+4 x-3\right)=?$
(a) (2x − 1) (2x − 3)(b) (2x + 1) (2x − 3)(c) (2x + 3) (2x − 1)(d) none of these
(c) $(2 x+3)(2 x-1)$
$4 x^{2}+4 x-3=4 x^{2}+6 x-2 x-3$
$=2 x(2 x+3)-1(2 x+3)$
$=(2 x+3)(2 x-1)$
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