Find the value
Question:
$\left(4 x^{2}+4 x-3\right)=?$
(a) (2x − 1) (2x − 3)
(b) (2x + 1) (2x − 3)
(c) (2x + 3) (2x − 1)
(d) none of these
Solution:
(c) $(2 x+3)(2 x-1)$
$4 x^{2}+4 x-3=4 x^{2}+6 x-2 x-3$
$=2 x(2 x+3)-1(2 x+3)$
$=(2 x+3)(2 x-1)$