Question:
Find the value
$1-27 a^{3}$
Solution:
$=(1)^{3}-(3 a)^{3}$
$=(1-3 a)\left(1^{2}+1 \times 3 a+(3 a)^{2}\right)$
$\therefore\left[a^{3}-b^{3}=(a-b)\left(a^{2}+a b+b^{2}\right)\right]$
$=(1-3 a)\left(1^{2}+3 a+9 a^{2}\right)$
$\therefore 1-27 a^{3}=(1-3 a)\left(1^{2}+3 a+9 a^{2}\right)$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.