Question:
Given that, $\sqrt{4096}=64$, the value of $\sqrt{4096}+\sqrt{40.96}$ is
(a) 74
(b) $60.4$
(c) $64.4$
(d) $70.4$
Solution:
(d) Given, $\sqrt{4096}=64$
So, $\sqrt{4096}+\sqrt{40.96}$
$=64+\sqrt{4096 \times 10^{-2}}$
$=64+\sqrt{4096} \sqrt{10^{-2}}$
$=64+64 \times 10^{-1}$
$=64+6.4=70.4$
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