Question:
How many 3-digit numbers can be formed by using the digits 0, 1, 3, 5, 7 while each digit may be repeated any number of times?
Solution:
100’s place 10’s place Unit’s place
There are total 5 digits available, for forming a 3 digit number, in 100's place only $1,3,5,7$ can be used( 0 not included because it will lead to formation of 2 digit number.) In 10 's place any of the 5 can be used and same is the case with one's place.
So total number of 3 digit numbers formed $=4 \times 5 \times 5=100$
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