How many bullets can be made out of a cube of lead, whose edge measures 22 cm,

Cube edge = 22 cm

Therefore volume of the cube $=(22)^{3}=10648 \mathrm{~cm}^{3}$

And,

Volume of each bullet $=4 / 3 \pi r^{3}$

$=4 / 3 \times 22 / 7 \times(1)^{3}$

= 4/3 × 22/7

$=88 / 21 \mathrm{~cm}^{3}$

Number of bullets $=\frac{\text { Volume of cube }}{\text { Volume of bullet }}=\frac{10648}{\frac{88}{21}}=2541$