Question:
If $-4$ is a zero of the quadratic polynomial $x^{2}-x-(2 k+2)$ then find the value of $k$
Solution:
Given: x = −4 is one zero of the polynomial x2 − x −(2k + 2)
Therefore, It will satisfy the above polynomial.
Now, we have
$(-4)^{2}-(-4)-(2 k+2)=0$
$\Rightarrow 16+4-2 k-2=0$
$\Rightarrow-2 k=-18$
$\Rightarrow k=9$