If 486*7 is divisible by 9, then the least value of * is

Question:

If 486*7 is divisible by 9, then the least value of * is

(a) 0

(b) 1

(c) 3

(d) 2

Solution:

(d) 2

For a number to be divisible by 9, the sum of its digits must be divisible by 9.

$4+8+6+^{*}+7=25+^{*}$

Now, $25+^{*}=27 \quad$ (if $^{*}=2$ and 27 is divisible by 9 )

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