If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is
(a) 1 : 3
(b) 1:2
(c) 3 : 1
(d) 1 : 4
(b) We know that, if a parallelogram and a triangle are on the same base and between the same parallels, then area of the triangle is half the area of
the parallelogram.
i.e., Area of triangle $=\frac{1}{2}$ Area of parallelogram
$\Rightarrow \quad \frac{\text { Area of triangle }}{\text { Area of parallelogram }}=\frac{1}{2}$
$\therefore$ Area of triangle : Area of parallelogram $=1: 2$
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