Question:
If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.
Solution:
True
Explanation:
From the given number, B+C is either 2 or the two digit number that gives the unit digit as 2.
It is given that B ≠ 0, C ≠ 0,
If B or C = 5 or 7, then A should be 3, then it becomes A+B+C = 14
Or else, if B= C = 6, and A = 2, we will get A+B+C = 14
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