Question:
If S and T are two sets such that S has 21 elements, T has 32 elements, and
S ∩ T has 11 elements, how many elements does S ∪ T have?
Solution:
It is given that:
n(S) = 21, n(T) = 32, n(S ∩ T) = 11
We know that:
n (S ∪ T) = n (S) + n (T) – n (S ∩ T)
∴ n (S ∪ T) = 21 + 32 – 11 = 42
Thus, the set (S ∪ T) has 42 elements.
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