If the curves

Question:

If the curves $\frac{x^{2}}{\alpha}+\frac{y^{2}}{4}=1$ and $y^{3}=16 x$ intersect at right angles, then a value of $\alpha$ is :

  1. $\frac{4}{3}$

  2. $\frac{3}{4}$

  3. $\frac{1}{2}$

  4. 2


Correct Option: 1

Solution:

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