Question:
If x and y vary inversely and x = 15 when y = 6, find y when x = 9.
Solution:
$x$ and $y$ var $y$ inversely.
i.e. $x y=$ constant
Now, $15 \times 6=9 \times y_{1}$
$\Rightarrow y_{1}=\frac{15 \times 6}{9}$
$\Rightarrow y_{1}=10$
$\therefore$ Value of $y=10$, when $x=9$
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