In 1CH2 = 2C = 3CH - 4CH3 molecule,

Question:

hybridization of carbon $1,2,3$ and 4 respectively are :

  1. $\mathrm{sp}^{3}, \mathrm{sp}, \mathrm{sp}^{3}, \mathrm{sp}^{3}$

  2. $\mathrm{sp}^{2}, \mathrm{sp}^{2}, \mathrm{sp}^{2}, \mathrm{sp}^{3}$

  3. $\mathrm{sp}^{2}, \mathrm{sp}, \mathrm{sp}^{2}, \mathrm{sp}^{3}$

  4. $\mathrm{sp}^{2}, \mathrm{sp}^{3}, \mathrm{sp}^{2}, \mathrm{sp}^{3}$

Correct Option: , 3

Solution:

$\left[\stackrel{1}{\mathrm{C}} \mathrm{H}_{2}=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathrm{H}-\stackrel{4}{\mathrm{C}} \mathrm{H}_{3}\right]$

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