In a ∆ABC it is given that base = 12 cm and height = 5 cm. Its area is

Question:

In a ABC it is given that base = 12 cm and height = 5 cm. Its area is

(a) $60 \mathrm{~cm}^{2}$

(b) $30 \mathrm{~cm}^{2}$

(c) $15 \sqrt{3} \mathrm{~cm}^{2}$

(d) $45 \mathrm{~cm}^{2}$

Solution:

(b) $30 \mathrm{~cm}^{2}$

Area of triangle $=\frac{1}{2} \times$ Base $\times$ Height

Area of $\triangle A B C=\frac{1}{2} \times 12 \times 5=30 \mathrm{~cm}^{2}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now