In ΔABC, ∠A = 50° and ∠B = 60°.

Question:

In ΔABC, ∠A = 50° and ∠B = 60°. Determine the longest and shortest sides of the triangle.

Solution:

Given: In ΔABC, ∠A = 50° and ∠B = 60°

In ΔABC,
A + ∠B + ∠C = 180°           (Angle sum property of a triangle)
">50° + 60° + ∠C = 180°
">110° + ∠C = 180°
">C = 180° -">- 110°
">C = 70°

Hence, the longest side will be opposite to the largest angle (∠C = 70°)  i.e. AB.
And, the shortest side will be opposite to the smallest angle (∠A = 50° ) i.e. BC.

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