In ∆ABC, side BC is produced to D. If ∠ABC = 50° and ∠ACD = 110° then ∠A = ?

Question:

In ∆ABC, side BC is produced to D. If ∠ABC = 50° and ∠ACD = 110° then A = ?
(a) 160°
(b) 60°
(c) 80°
(d) 30°

 

Solution:

$\therefore \angle A+\angle B=\angle A C D$

$\Rightarrow \angle A+50^{\circ}=110^{\circ}$

$\Rightarrow \angle A=60^{\circ}$

Hence, the correct answer is option (b).

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