Question:
In Fig. 17.28, ABCD and AEFG are parallelograms. If ∠C = 55°, what is the measure of ∠F?
Solution:
Both the parallelograms $\mathrm{ABCD}$ and $\mathrm{AEFG}$ are similar.
$\therefore \angle \mathrm{C}=\angle \mathrm{A}=55^{\circ}$ (opposite angles of a parallelogram are equal)
$\therefore \angle \mathrm{A}=\angle F=55^{\circ} \quad$ (opposite angles of a parallelogram are equal)
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