Question:
In figure, ABCD is a trapezium in which AB ∥ DC. Prove that ar(ΔAOD) = ar(ΔBOC)
Solution:
Given: ABCD is a trapezium in which AB ∥ DC
To prove: ar(ΔAOD) = ar(ΔBOC)
Proof: Since, ΔADC and ΔBDC are on the same base DC and between same parallels AB and DC
Then, ar(ΔADC) = ar(ΔBDC)
⇒ ar(ΔAOD) + ar(ΔDOC) = ar(ΔBOC) + ar(ΔDOC)
⇒ ar(ΔAOD) = ar(ΔBOC)
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