Question:
In the given below figure, find x. Further find ∠COD, ∠AOD, ∠BOC
Solution:
Since ∠AOD and ∠BOD form a line pair,
∠AOD + ∠BOD = 180°
∠AOD + ∠BOC + ∠COD = 180°
Given that,
∠AOD = (x + 10)°, ∠COD = x°, ∠BOC = (x + 20)°
(x + 10) + x + (x + 20) = 180
3x + 30 = 180
3x = 180 - 30
3x = 150/3
x = 50
Therefore, ∠AOD = (x + 10)
= 50 + 10 = 60
∠COD = x = 50°
∠COD = (x + 20)
= 50 + 20 = 70
∠AOD = 60°∠COD = 50°∠BOC = 70°
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.