In the hydroboration - oxidation

Question:

In the hydroboration - oxidation reaction of propene with diborane, $\mathrm{H}_{2} \mathrm{O}_{2}$ and $\mathrm{NaOH}$, the organic compound formed is :

  1. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$

  2. $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}$

  3. $\mathrm{CH}_{3} \mathrm{CHOHCH}_{3}$

  4. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$

Correct Option: 1

Solution:

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