Let R be a relation on N defined by x + 2y = 8.

Question:

Let R be a relation on N defined by x + 2y = 8. The domain of R is

(a) [2, 4, 8]

(b) [2, 4, 6, 8]

(c) [2, 4, 6]

(d) [1, 2, 3, 4]

Solution:

(c) {2, 4, 6}

x + 2y = 8

 x = 8 -">- 2y

For y = 1, x = 6

y = 2, x = 4

y = 3, x = 2

Then R = {(2,3),(4,2),(6,1)}

∴ Domain of R = {2,4,6}

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