Question:
Mark (✓) against the correct answer
$\left(\frac{-1}{3}\right)^{3}=?$
(a) $\frac{-1}{9}$
(b) $\frac{1}{9}$
(c) $\frac{-1}{27}$
(d) $\frac{1}{27}$
Solution:
(c) $\frac{-1}{27}$
$\left(\frac{-1}{3}\right)^{3}=\frac{-1^{3}}{3^{3}}=\frac{-1}{27}$
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