Question:
Mark (✓) against the correct answer
$\frac{4}{3} \div ?=\frac{-5}{2}$
(a) $\frac{-8}{5}$
(b) $\frac{8}{5}$
(C) $\frac{-8}{15}$
(d) $\frac{8}{15}$
Solution:
(c) $\frac{-8}{15}$
We have:
$\frac{4}{3} \div x=\frac{-5}{2}$
$\Rightarrow \frac{4}{3} \times \frac{1}{x}=\frac{-5}{2}$
$\Rightarrow \frac{1}{x}=\frac{\left(\frac{-5}{2}\right)}{\left(\frac{4}{3}\right)}$
$\Rightarrow \frac{1}{x}=\left(\frac{-5}{2}\right) \times\left(\frac{3}{4}\right)$
$\Rightarrow \frac{1}{x}=\frac{-15}{8}$
$\Rightarrow x=\frac{8}{-15}=\frac{8 \times-1}{-15 \times-1}=\frac{-8}{15}$
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