Question:
Mark (✓) against the correct answer:
How many diagonals are there in a hexagon?
(a) 6
(b) 8
(c) 9
(d) 10
Solution:
(c) 9
Hexagon has six sides.
Number of diagonals $=\frac{n(n-3)}{2} \quad$ (where $n$ is the number of side $s$ )
$=\frac{6(6-3)}{2}$
$=9$
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