Mark (✓) against the correct answer:

Question:

Mark (✓) against the correct answer:

Two opposite angles of a parallelogram are (3x − 2)° and (50 − x)°. The measures of all its angles are

(a) 97°, 83°, 97°, 83°

(b) 37°, 143°, 37°, 143°

(c) 76°, 104°, 76°, 104°

(d) none of these

Solution:

(b) 37o, 143o, 37o 143o

Opposite angles of a parallelogram are equal.

$\therefore 3 x-2=50-x$

$\Rightarrow 3 x+x=50+2$

$\Rightarrow 4 x=52$

$\Rightarrow x=13$

Therefore, the first and the second angles are:

$(3 x-2)^{\circ}=(2 \times 13-2)^{\circ}=37^{\circ}$

$(50-x)^{\circ}=(50-13)^{\circ}=37^{\circ}$

Sum of adjacent angles in a parallelogram is $180^{\circ}$.

Adjacent angles $=180^{\circ}-37^{\circ}=143^{\circ}$

 

 

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now