Mark against the correct answer in each of the following:

Question:

Mark $(\sqrt{)}$ against the correct answer in each of the following:

$\int \tan ^{-1}\left\{\sqrt{\frac{1-\cos 2 x}{1+\cos 2 x}}\right\} d x=?$

A. $\frac{-1}{\left(1+x^{2}\right)}+C$

B. $\frac{1}{\sqrt{1+x^{2}}}+C$

C. $\frac{1}{\sqrt{1-x^{2}}}+C$

D. $\frac{x^{2}}{2}+C$

Solution:

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