Mark the correct alternative in the following:

Question:

Mark the correct alternative in the following:

Function $f(x)=|x|-|x-1|$ is monotonically increasing when

A. $x<0$

B. $x>1$

C. $x<1$

D. $0

Solution:

Formula:- (i) The necessary and sufficient condition for differentiable function defined on (a,b) to be strictly increasing on $(a, b)$ is that $f^{\prime}(x)>0$ for $a l l ~ x \in(a, b)$

Given:-

For $x<0$

$f(x)=-1$

for $0

$f(x)=2 x-1$

for $x>1$

$f(x)=1$

Hence $f(x)$ will increasing in $0

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